241) sum of forces = m*a,
X- Dirn
ma = T
m(woman)*a=T
Y- Dirn
ma = Fg -T
m(block)*a=m(block)*g-T
From X Dirn, a=T/m(woman)
m(block)*T/m(woman)=m(block)*g-T
since m(block) = m(woman) in this case
T=m(block)*g-T
2*T =m(block)*g
T = m(block)*g/2
T = 50*10/2 = 250 N
242)
Same as above but:
m(block)*T/m(man)=m(block)*g-T
(50/100)T = m(block)*g-T
T/2 = m(block)*g-T
T/2 + T = m(block)*g
(3/2)T = m(block)*g
T = m(block)*g *(2/3)
T = 50 * 10 * 2 / 3
T = 1000/3
T = 333 N
Cheers
Mitchell