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Physics 1001, Q.290
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umghai
#1 Posted : Tuesday, July 19, 2011 10:57:33 PM
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Hi! I was wondering if anyone can help me on Q.290, from the Physics 1001 exam cracker booklet.
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AndersonMD
#2 Posted : Friday, July 22, 2011 1:26:30 PM
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Hi

The maximum apparent weight F = Fg + ma = m (g+a), when you start the trip from 3rd to 1st floor you are accelerating down, so F = m (g-a)= 10 (10-1) = 90 N, when traveling at a constant speed F = 10 (10 - 0) = 100 N, and when slowing down at the bottom F = 10 (10 - (-1)) = 110 N. So the maximum apparent weight is when you are slowing down and is 110 N.

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Mitchell
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