Welcome Guest Search | Active Topics |

Tag as favorite
Calculating mL in a M concentration with litres and moles problems
ngofine
#1 Posted : Wednesday, July 23, 2014 2:29:11 AM
Rank: Newbie

Groups: Registered
Joined: 4/3/2014
Posts: 3

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Can anyone explain this concept to me? I know it looks so simple but I am confused and cant seem to figure it out and its always coming up in past questions with mcat. I will appreciate your prompt response as my mcat is this friday.

Thanks
finolahackett
#2 Posted : Wednesday, July 23, 2014 6:53:12 PM
Rank: Instructor

Groups: Registered
Joined: 5/30/2014
Posts: 1

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Concentration in terms of M (molarity) = moles solute/volume of solution.
M is usually given in units of mol/L.
To calculate volume, divide the number of moles by the concentration.
M = n/V so V = n/M

Ex. What is the volume of 2 M NaOH needed to react with 3 moles of H+ ions?
V = n/M = 3 moles / 2 mol/L = 1.5 L

To convert L to mL, multiply by 1000.
Ex. 1.5 L = 1500 mL

Don't forget to use the stoichiometric coefficients (mole ratio) of the balanced reaction when converted between chemical species!
(the ratio above is 1:1 since 1 OH- reacts with 1 H+)

Hope this helps.

Finola
Users browsing this topic
Guest (2)
Tag as favorite
You cannot post new topics in this forum.
You cannot reply to topics in this forum.
You cannot delete your posts in this forum.
You cannot edit your posts in this forum.
You cannot create polls in this forum.
You cannot vote in polls in this forum.

Clean Slate theme by Jaben Cargman (Tiny Gecko)
Powered by YAF | YAF © 2003-2009, Yet Another Forum.NET
This page was generated in 0.110 seconds.