Hi leahjinx,
You are on the right track. You can break up this problem into 2 parts.
Part 1: isometric contraction --> F(net) = 0
F(gravity) is reduced, so F(muscle) is reduced.
You can think of this part as "controlling for gravity".
Part 2: concentric contraction --> F(net) > 0
The added F(muscle) is the same, so F(net) is the same.
Thus, acceleration will also be the same.
Although a smaller F(muscle) is used to control for gravity, the isometric contraction in both cases brings the system to equilibrium before increasing the stimulation by an equal amount.
Regards,
Milad