Welcome Guest Search | Active Topics |

Tag as favorite
EK Study Guide Lecture Questions
Janelle_5719
#1 Posted : Tuesday, June 02, 2020 10:17:46 PM
Rank: Newbie

Groups: Registered
Joined: 5/18/2020
Posts: 8

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Hi there,

I have a few questions from Lecture 2 of the EK Study Guide: (pg.41-70)

- Question #32: What is the difference between bond energy and bond dissociation energy? Is there a difference?
- Question #42: How do we know what the orientation of the Br is? How do we know it goes into the page rather than out of the page?
-Question #44: How do we know that the answer B is symmetrical? What would the actual structure of B look like?

Thank you!
INSTR_Kailey_109
#2 Posted : Friday, June 05, 2020 6:55:10 PM
Rank: Advanced Member

Groups: Registered
Joined: 6/4/2020
Posts: 31

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Question #32: For the level of Chemistry generally covered on the MCAT, the difference between bond energy and bond dissociation energy is generally not significant.

For a more detailed answer: bond dissociation energy is a very specific definition that it refers to splitting the enthalpy change during the process of a bond “equally” being split into two radicals (homolysis) at 0 K.

This energy is always the same under these conditions assuming that the particle is in a vacuum. However, real life is more complicated, and bond energy reflects that. For example, breaking a bond will have slightly different energy if it is broken heterolytically – that is if you deprotonate water to OH-, that bond energy is not the same as the bond dissociation. In short, bond dissociation energy and bond energy both generally track the same way with bond length and strength but vary slightly in their exact values.


Question #42: By convention, a wedge bond signifies an atom coming out of the page and a hash (dash) bond signifies the bond going into the page. A wedge looks like a bold triangle and a hash bond a set of parallel lines.

For this question, the challenge is that the molecule is flipped over in the answer in addition to the displacement taking place. Keep in mind that an Sn2 is an inversion of the stereocenter, and when you flip over a molecule, you change hash bonds to wedge bonds and vice versa.


Question #44: To know a molecule is symmetrical, we look for a mirror plane within it. For this example, it is easier to see that B is symmetrical using the Fischer projection. Recall that you cannot rotate the stereocenters within a fischer projection, but you can rotate the ends of it (here there are only ends). Often to be extra tricky, we’ll show a molecule that needs to be rotated to clearly see its mirror plane. I have shown you this rotation here in a picture.

mirror plane image

For Fischer projections, a molecule is bent over like a bridge. To deconvolute one, you imagine flying over the top of the fischer projection. The horizonal lines come out to hug you and the vertical lines are curved away from you. In addition, anything to your left becomes a wedge, and anything to your right becomes a dash, to keep track of your rotating point of view.
Users browsing this topic
Guest
Tag as favorite
You cannot post new topics in this forum.
You cannot reply to topics in this forum.
You cannot delete your posts in this forum.
You cannot edit your posts in this forum.
You cannot create polls in this forum.
You cannot vote in polls in this forum.

Clean Slate theme by Jaben Cargman (Tiny Gecko)
Powered by YAF | YAF © 2003-2009, Yet Another Forum.NET
This page was generated in 0.090 seconds.