Welcome Guest Search | Active Topics |

Tag as favorite
AAMC physics question - wavelength equation
Sophia_6535
#1 Posted : Saturday, June 19, 2021 11:28:58 PM
Rank: Member

Groups: Registered
Joined: 4/25/2021
Posts: 10

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Hi,

I am having issues with this question:

Consecutive resonances occur at wavelengths of 8 m and 4.8 m in an organ pipe closed at one end. What is the length of the organ pipe? (Note: Resonances occur at L = nλ/ 4, where L is the pipe length, λ is the wavelength, and n = 1, 3, 5,…)

I understand that L = nλ/4 needs to be used but when looking at the answers the math confuses me and I become unsure of how to solve it

Answer: 6m

Any help is appreciated!
INSTR_Calla_139
#2 Posted : Tuesday, June 22, 2021 7:34:33 PM
Rank: Member

Groups: Registered
Joined: 6/8/2021
Posts: 13

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Hello Sophia,

Using the equation L = nλ/4 I would start by figuring out which variables I know:

I know that these two wavelengths are occurring at n=3 and n=5 (it says they must be consecutive resonances) because these two ns workout to have the same length of pipe.

I also know that λ=8m and λ=4.8m

We are solving for L, which will be constant so you can also think about it like L=n₁*8/4=n₂*4.8/4. so of the possible n values, what multiplied by 8 will equal the same value as the next odd integer multiplied by 4.8?

L= (3*8)/4 = 6m
L=(5*4.8)/4 = 6m

Hope this helps a little bit

Users browsing this topic
Guest
Tag as favorite
You cannot post new topics in this forum.
You cannot reply to topics in this forum.
You cannot delete your posts in this forum.
You cannot edit your posts in this forum.
You cannot create polls in this forum.
You cannot vote in polls in this forum.

Clean Slate theme by Jaben Cargman (Tiny Gecko)
Powered by YAF | YAF © 2003-2009, Yet Another Forum.NET
This page was generated in 0.053 seconds.