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 Nicole_5521 #1 Posted : Saturday, July 31, 2021 3:37:09 PM Rank: Advanced MemberGroups: Registered Joined: 4/30/2020Posts: 71Thanks: 0 timesWas thanked: 0 time(s) in 0 post(s) Hi,For Q48, could you explain why there needs to be a saturated substrate concentration in order to measure kcat?For Q51, I'm confused why peptide C has a charge of -1? Doesn't it have a charge of 0 because H (+1), E (-1), E (-1), K (+1), R (+1), D (-1)? For Q57, how come the volume changes are getting multiplied to the concentration? I'm confused because is concentration=moles/volume, so if the volume increases doesn't that make the concentration smaller? But, we are multiplying the concentration to make it larger here?Thanks! Back to top User Profile
 INSTR_Molly_129 #2 Posted : Saturday, July 31, 2021 9:38:56 PM Rank: Advanced MemberGroups: Registered Joined: 5/23/2021Posts: 74Thanks: 0 timesWas thanked: 0 time(s) in 0 post(s) Hi Nicole,I'm unfortunately unable to see some of the questions that you are referring to, but I will answer 57 which matches what you are describing here. Hopefully another moderator could assist.Q57: For the experiment, the commercial concentration was diluted from 0.1 mL to 25 mL, so the concentration had decreased by a factor of 250x. Then in the assay, 1 mL of the enzyme and 1 mL of the substrate was mixed, so concentration was further decreased by a factor of 2x. Overall, the concentration was decreased 250 x 2, which is 500.Hope that helps!Molly Back to top User Profile
 Nicole_5521 #3 Posted : Saturday, July 31, 2021 10:02:19 PM Rank: Advanced MemberGroups: Registered Joined: 4/30/2020Posts: 71Thanks: 0 timesWas thanked: 0 time(s) in 0 post(s) Hi Molly,If the concentration decreases, how come you would multiply the concentration by 500 in the answer choice? Wouldn't you have to divide to show it decreasing?Thanks! Back to top User Profile