Welcome Guest Search | Active Topics |

Tag as favorite
ICE 7 Questions
Janelle_5719
#1 Posted : Tuesday, June 02, 2020 10:38:46 PM
Rank: Newbie

Groups: Registered
Joined: 5/18/2020
Posts: 8

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
(Pg.306-310)
- Question #140: Why would PH not stay the same if the kw of water increases? Why would PH decrease instead? Would the concentration of OH not increase proportionally thus keeping the PH neutral?

- Question #142: I do not understand why acetic acid being a weaker base than water would result in different concentrations of H+ in that but not in water?

-Question #143: Why would water not be in the denominator for the equation? Isn't water a gas at 50 degrees Celsius therefore it should be included in the Kw equation?
Leanne_5424
#2 Posted : Thursday, June 04, 2020 2:08:35 PM
Rank: Newbie

Groups: Registered
Joined: 6/3/2020
Posts: 1

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Janelle_5719 wrote:
(Pg.306-310)
- Question #140: Why would PH not stay the same if the kw of water increases? Why would PH decrease instead? Would the concentration of OH not increase proportionally thus keeping the PH neutral?

- Question #142: I do not understand why acetic acid being a weaker base than water would result in different concentrations of H+ in that but not in water?

-Question #143: Why would water not be in the denominator for the equation? Isn't water a gas at 50 degrees Celsius therefore it should be included in the Kw equation?




Actually to add on to Janelle's question regarding Q142 - I'm confused as to how acetic acid is acting as a base compared to water. Is it the acetate ion that the ExamKrackers is referring to instead of acetic acid when saying that it's a weaker base than water?
INSTR_Kailey_109
#3 Posted : Friday, June 05, 2020 6:56:25 PM
Rank: Advanced Member

Groups: Registered
Joined: 6/4/2020
Posts: 31

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Question #140: Keep in mind that pH is defined as the -log[H+], or the negative log of the concentration of H+ ions. If Kw = k[H+][OH-], and Kw increases, then both the concentration of OH- and H+ increase. However, as the definition of pH only depends on the concentration of H+, you only consider the H+ increase. In reality, you are correct and the OH- concentration also rises, but this is not relevant to the definition of pH.

In fact, the sum of the two in the equation pKw = pH + pH just changes such that pKw is not equal to 14, but a greater number. It is interesting to see how acidity and basicity depend on temperature!


Question #142: This question can be a little tricky! Here, the key is that HCl and HClO4 are both strong acids in water, and that means they both fully dissociate in water. As a result, we do not know which acid is stronger in water, because they both fully dissociate. To figure out which acid is stronger, we need to create conditions where one acid fully dissociates and the other does not. As a result, we want to have something that “wants protons less” than water does. Acetic acid is less easily protonated than water is, and therefore it can show the difference in acid strength between HCl and HClO4.

This is known as the leveling effect. A good analogy is that of a test. For a teacher to figure out which of two students is more advanced in math, it is not sufficient to give the two students an easier test on addition and subtraction, because both of them will get 100%. What you need to see which student knows more is a harder test where one or both will not get 100%.


Question #143: Because water has constant concentration, it is not included in Keq equations like the Kw equation. The Kw equation is Kw = k[H+][OH-]. This is a great way to eliminate answers on the MCAT. If you are given a solid or liquid phase in a Keq equation, this is not possible as their concentrations are constant.
INSTR_Kailey_109
#4 Posted : Friday, June 05, 2020 6:57:36 PM
Rank: Advanced Member

Groups: Registered
Joined: 6/4/2020
Posts: 31

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Leanne_5424 wrote:
Janelle_5719 wrote:
(Pg.306-310)
- Question #140: Why would PH not stay the same if the kw of water increases? Why would PH decrease instead? Would the concentration of OH not increase proportionally thus keeping the PH neutral?

- Question #142: I do not understand why acetic acid being a weaker base than water would result in different concentrations of H+ in that but not in water?

-Question #143: Why would water not be in the denominator for the equation? Isn't water a gas at 50 degrees Celsius therefore it should be included in the Kw equation?




Actually to add on to Janelle's question regarding Q142 - I'm confused as to how acetic acid is acting as a base compared to water. Is it the acetate ion that the ExamKrackers is referring to instead of acetic acid when saying that it's a weaker base than water?



For acid and base chemistry, it is important to compare apples to apples. The acetate ion is to acetic acid what OH- is to water. If we think about using acetic acid as a solvent, because it is a weak acid, pure acetic acid is largely dissociated because there is no water to donate its proton to. Therefore, we are comparing the protonation of acetic acid in this question and not the acetate anion. This protonated acetic acid doesn't really exist in large quantities in water as it itself is also a strong acid in water.

I would say that this is not common to see as most of the chemistry on the MCAT is biologically relevant - this question involves using acetic acid as a solvent, which is not the most biologically relevant thing in the world.

See the image here
Users browsing this topic
Guest (4)
Tag as favorite
You cannot post new topics in this forum.
You cannot reply to topics in this forum.
You cannot delete your posts in this forum.
You cannot edit your posts in this forum.
You cannot create polls in this forum.
You cannot vote in polls in this forum.

Clean Slate theme by Jaben Cargman (Tiny Gecko)
Powered by YAF | YAF © 2003-2009, Yet Another Forum.NET
This page was generated in 0.179 seconds.