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practise set 7 #54
Brittany_6462
#1 Posted : Friday, May 28, 2021 11:40:17 PM
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How does 4M become 300g/L, I am confused about the calculations happening in between
INSTR_Katrina_128
#2 Posted : Sunday, May 30, 2021 5:21:51 PM
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We are going to assume that the 4 M solution of KCl is a saturated solution. In other words, the maximum amount of KCl that can dissolve in water is 4 mol / 1 L of water.

Well, if we can turn that 4 mol / 1 L into MASS / 1 L, then we have our answer!

The key is to determine the molar mass of KCl.

Potassium has a molar mass of 39.0 g/mol.

Chlorine has a molar mass of 35.5 g/mol.

Therefore, KCl has a molar mass of 74.5 g/mol, or approximately 75 g/mol.

4 mol of KCl is 4x75 = 300 g

Therefore, 4 M KCl is equivalent to 300 g / L.
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