Welcome Guest Search | Active Topics |

Tag as favorite
AAMC Section Bank CP
Nicole_5521
#1 Posted : Saturday, July 31, 2021 3:37:09 PM
Rank: Advanced Member

Groups: Registered
Joined: 4/30/2020
Posts: 71

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Hi,

For Q48, could you explain why there needs to be a saturated substrate concentration in order to measure kcat?

For Q51, I'm confused why peptide C has a charge of -1? Doesn't it have a charge of 0 because H (+1), E (-1), E (-1), K (+1), R (+1), D (-1)?

For Q57, how come the volume changes are getting multiplied to the concentration? I'm confused because is concentration=moles/volume, so if the volume increases doesn't that make the concentration smaller? But, we are multiplying the concentration to make it larger here?

Thanks!
INSTR_Molly_129
#2 Posted : Saturday, July 31, 2021 9:38:56 PM
Rank: Advanced Member

Groups: Registered
Joined: 5/23/2021
Posts: 74

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Hi Nicole,

I'm unfortunately unable to see some of the questions that you are referring to, but I will answer 57 which matches what you are describing here. Hopefully another moderator could assist.

Q57: For the experiment, the commercial concentration was diluted from 0.1 mL to 25 mL, so the concentration had decreased by a factor of 250x. Then in the assay, 1 mL of the enzyme and 1 mL of the substrate was mixed, so concentration was further decreased by a factor of 2x. Overall, the concentration was decreased 250 x 2, which is 500.

Hope that helps!

Molly
Nicole_5521
#3 Posted : Saturday, July 31, 2021 10:02:19 PM
Rank: Advanced Member

Groups: Registered
Joined: 4/30/2020
Posts: 71

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Hi Molly,

If the concentration decreases, how come you would multiply the concentration by 500 in the answer choice? Wouldn't you have to divide to show it decreasing?

Thanks!
INSTR_Katrina_128
#4 Posted : Tuesday, August 03, 2021 5:12:30 PM
Rank: Advanced Member

Groups: Registered
Joined: 5/18/2021
Posts: 73

Thanks: 0 times
Was thanked: 0 time(s) in 0 post(s)
Q48: This is asking about Michaelis-Menten kinetics.

There are two sections of the Michaelis-Menten graph: when the enzyme is unsaturated and when the enzyme is saturated.

https://lh3.googleuserco..._8dmTGCAPjrzITeYrT44mFI

It is MUCH easier to measure the rate constant of the catalyst (kcat) when [S] is saturated, because you're in that flat region, where kcat stops changing.

When [S] is too low, then you need to find the slope of the line, and relate it to kcat/KM, meaning you also need to know KM. Not fun. So, dump a ton of substrate in until the rate of product formation doesn't change, and you know you're in the right spot!

Q51: Be careful! At pH = 7, histidine is UNCHARGED (neutral).

Here are the total charged species:

Two glutamic acids and one aspartic acid (-3).

One lysine and one arginine (+2).

Overall: -1.

Q57: I think you're thinking about it backwards. Here, they're asking you to start with the diluted concentration, and then figure out the more concentrated stuff. That's why we're multiplying!
Users browsing this topic
Guest
Tag as favorite
You cannot post new topics in this forum.
You cannot reply to topics in this forum.
You cannot delete your posts in this forum.
You cannot edit your posts in this forum.
You cannot create polls in this forum.
You cannot vote in polls in this forum.

Clean Slate theme by Jaben Cargman (Tiny Gecko)
Powered by YAF | YAF © 2003-2009, Yet Another Forum.NET
This page was generated in 0.098 seconds.